Chapter at a Glance

Here is the whole of Arithmetic Progressions on one page — perfect for the night before your exam.

Basics

  • An AP adds a fixed common difference dd to each term.
  • First term aa; general form a,a+d,a+2d,a, a+d, a+2d, \dots
  • d=an+1and = a_{n+1} - a_n (any term minus the previous).
  • Test for AP: consecutive differences are all equal.

Remember: dd can be positive, negative, or zero. A constant difference is the signature of an AP.

Key Formulae (Must Memorise)

nth term

an=a+(n1)da_n = a + (n - 1)d (Note: (n1)(n-1), not nn.)

Sum of first n terms

Sn=n2[2a+(n1)d]=n2(a+l)S_n = \frac{n}{2}\left[2a + (n - 1)d\right] = \frac{n}{2}(a + l) where ll is the last term.

Term from sum

an=SnSn1a_n = S_n - S_{n-1}

nth term from the end

l(n1)dl - (n - 1)d

Key Point: Use ana_n for a single position, SnS_n for a total. The second sum formula is fastest when ll is known.

Arithmetic Mean and Term Selection

Arithmetic mean

If a,b,ca, b, c are in AP, b=a+c2b = \dfrac{a + c}{2}. Three numbers are in AP iff 2b=a+c2b = a + c.

Inserting kk means between aa and bb

d=bak+1d = \frac{b - a}{k + 1}

Choosing terms symmetrically

  • Three terms: ad,a,a+da - d, a, a + d (sum =3a= 3a).
  • Four terms: a3d,ad,a+d,a+3da - 3d, a - d, a + d, a + 3d (sum =4a= 4a, common difference 2d2d).

Key Point: Symmetric choices make the sum independent of dd, so the sum condition gives aa at once.

Word-Problem Cues

  • 'In the nnth year/month/row' → nth term ana_n.
  • 'Total over nn years/terms' → sum SnS_n.
  • 'Increases/decreases by a fixed amount each …' signals an AP.
  • Simple interest amounts form an AP (fixed amount added yearly).
  • Seats in rows, logs stacked, prizes decreasing — all APs.
  • Two data points (e.g. value in year 3 and year 7) → form a+2da + 2d and a+6da + 6d to find aa, dd.

Key Point: Translate worded positions correctly: 'year 3' is a3=a+2da_3 = a + 2d, not a+3da + 3d.

Last-Minute Tips and Common Traps

  • Use (n1)d(n-1)d in the nth term — never ndnd.
  • When finding nn from a sum, you get a quadratic; both positive roots may be valid, or reject negatives/fractions.
  • Reject any answer that makes a count or term physically impossible (e.g. negative logs).
  • 'year 3' = a+2da + 2d; read positions carefully.
  • Sn=n2(a+l)S_n = \dfrac{n}{2}(a + l) is quickest with a known last term.
  • A non-integer nn when solving an=a_n = value means the value is not a term.

Final Word: Arithmetic Progressions is a reliable, formula-driven chapter. Master the nth-term and sum formulae and the word-problem setups, and you secure most of the marks. All the best!