Introduction

Sequence

A sequence is an ordered list of numbers. The various numbers occurring in a sequence are called its terms.

  • Denoted by a1,a2,a3,,an,a_1, a_2, a_3, \dots, a_n, \dots.
  • A sequence containing a finite number of terms is called a finite sequence.
  • A sequence is called infinite if it is not a finite sequence.

Series

If a1,a2,a3,,ana_1, a_2, a_3, \dots, a_n is a sequence, then the expression a1+a2+a3++ana_1 + a_2 + a_3 + \dots + a_n is called the series associated with the sequence.


Arithmetic Progression (A.P.)

A sequence in which the difference between any two consecutive terms is constant.

Standard Form

a,a+d,a+2d,a+3d,a, a+d, a+2d, a+3d, \dots

  • aa = first term
  • dd = common difference

Formulas

  1. General Term (nthn^{th} term): an=a+(n1)da_n = a + (n-1)d
  2. Sum of first nn terms: Sn=n2[2a+(n1)d]S_n = \frac{n}{2}[2a + (n-1)d] Sn=n2(a+l)(where l=an is last term)S_n = \frac{n}{2}(a + l) \quad \text{(where } l = a_n \text{ is last term)}

Arithmetic Mean (A.M.)

If a,A,ba, A, b are in A.P., then AA is the arithmetic mean of aa and bb. A=a+b2A = \frac{a+b}{2}


Geometric Progression (G.P.)

A sequence in which the ratio of any term to its preceding term is constant.

Standard Form

a,ar,ar2,ar3,a, ar, ar^2, ar^3, \dots

  • aa = first term
  • rr = common ratio

Formulas

  1. General Term (nthn^{th} term): an=arn1a_n = ar^{n-1}
  2. Sum of first nn terms: Sn=a(rn1)r1if r1S_n = \frac{a(r^n - 1)}{r - 1} \quad \text{if } r \neq 1
  3. Sum of Infinite G.P. (r<1|r| < 1): S=a1rS_\infty = \frac{a}{1 - r}

Geometric Mean (G.M.)

If a,G,ba, G, b are in G.P., then GG is the geometric mean of aa and bb. G=abG = \sqrt{ab}


Relationship Between A.M. and G.M.

For any two positive real numbers aa and bb: A.M.G.M.A.M. \ge G.M. Equality holds if and only if a=ba = b.


Sum of Special Series

  1. Sum of first nn natural numbers: k=1nk=n(n+1)2\sum_{k=1}^n k = \frac{n(n+1)}{2}
  2. Sum of squares of first nn natural numbers: k=1nk2=n(n+1)(2n+1)6\sum_{k=1}^n k^2 = \frac{n(n+1)(2n+1)}{6}
  3. Sum of cubes of first nn natural numbers: k=1nk3=[n(n+1)2]2\sum_{k=1}^n k^3 = \left[ \frac{n(n+1)}{2} \right]^2

Common Mistakes

  1. Confusing dd (difference) with rr (ratio).
  2. Using G.P. formula for A.P. or vice-versa.
  3. Wrong substitution of nn.
  4. Forgetting condition r<1|r|<1 for infinite G.P.
  5. Writing wrong last term in A.P.

Sequences and Series

Example 1

Find the 10th term of the sequence defined by an=2n2+1a_n = 2n^2 + 1.

Solution: Put n=10n=10: a10=2(10)2+1=200+1=201a_{10} = 2(10)^2 + 1 = 200 + 1 = 201.


Example 2

In an A.P., if a=5a=5 and d=3d=-3, find the 12th term.

Solution: a12=a+11d=5+11(3)=533=28a_{12} = a + 11d = 5 + 11(-3) = 5 - 33 = -28.


Example 3

Which term of the A.P. 3, 8, 13, … is 78?

Solution: a=3,d=5a=3, d=5. Let an=78a_n = 78. 3+(n1)5=78    5(n1)=75    n1=15    n=163 + (n-1)5 = 78 \implies 5(n-1) = 75 \implies n-1 = 15 \implies n=16.


Example 4

Find the sum of the first 20 terms of the A.P. 1, 4, 7, 10…

Solution: a=1,d=3,n=20a=1, d=3, n=20. S20=202[2(1)+19(3)]=10[2+57]=590S_{20} = \frac{20}{2}[2(1) + 19(3)] = 10[2 + 57] = 590.


Example 5

Insert 3 arithmetic means between 3 and 19.

Solution: Let means be A1,A2,A3A_1, A_2, A_3. Sequence: 3, A1,A2,A3A_1, A_2, A_3, 19. Total terms = 5. a5=3+4d=19    4d=16    d=4a_5 = 3 + 4d = 19 \implies 4d = 16 \implies d=4. Means: 3+4=7,7+4=11,11+4=153+4=7, 7+4=11, 11+4=15.


Example 6

Find the 7th term of the G.P. 2, 4, 8, 16…

Solution: a=2,r=2a=2, r=2. a7=ar6=2(2)6=27=128a_7 = ar^6 = 2(2)^6 = 2^7 = 128.


Example 7

Find the sum of G.P. 1+12+14+1 + \frac{1}{2} + \frac{1}{4} + \dots up to 8 terms.

Solution: a=1,r=1/2a=1, r=1/2. S8=1(1(1/2)8)11/2=11/2561/2=2×255256=255128S_8 = \frac{1(1 - (1/2)^8)}{1 - 1/2} = \frac{1 - 1/256}{1/2} = 2 \times \frac{255}{256} = \frac{255}{128}.


Example 8

Find sum to infinity of G.P. 5, 2.5, 1.25…

Solution: a=5,r=0.5a=5, r=0.5. S=a1r=510.5=10S_\infty = \frac{a}{1-r} = \frac{5}{1-0.5} = 10.


Example 9

Find the geometric mean of 4 and 9.

Solution: G=4×9=36=6G = \sqrt{4 \times 9} = \sqrt{36} = 6.


Example 10

If A.M. and G.M. of two numbers are 10 and 8 respectively, find the numbers.

Solution: a+b=20,ab=64a+b=20, ab=64. Quadratic: x220x+64=0x^2 - 20x + 64 = 0. Roots are 16 and 4. Numbers are 4, 16.


Example 11

Find the sum of first nn odd natural numbers.

Solution: A.P. 1, 3, 5… a=1,d=2a=1, d=2. Sn=n2[2+(n1)2]=n2[2n]=n2S_n = \frac{n}{2}[2 + (n-1)2] = \frac{n}{2}[2n] = n^2.


Example 12

Evaluate k=110(2k+3)\sum_{k=1}^{10} (2k + 3).

Solution: =2k+3=210(11)2+10(3)=110+30=140= 2\sum k + \sum 3 = 2\frac{10(11)}{2} + 10(3) = 110 + 30 = 140.


Example 13

Which term of G.P. 2, 8, 32 … is 131072?

Solution: a=2,r=4a=2, r=4. 24n1=131072    4n1=65536=482 \cdot 4^{n-1} = 131072 \implies 4^{n-1} = 65536 = 4^8. n1=8    n=9n-1 = 8 \implies n=9.


Example 14

If sum of 3 numbers in A.P. is 24 and their product is 440, find the numbers.

Solution: Let numbers be ad,a,a+da-d, a, a+d. Sum =3a=24    a=8= 3a = 24 \implies a=8. Product: 8(64d2)=440    64d2=55    d2=9    d=±38(64-d^2) = 440 \implies 64-d^2 = 55 \implies d^2 = 9 \implies d=\pm 3. Numbers: 5, 8, 11.


Example 15

Calculate 12+22++1021^2 + 2^2 + \dots + 10^2.

Solution: Formula: n(n+1)(2n+1)6\frac{n(n+1)(2n+1)}{6}. For n=10n=10: 10(11)(21)6=385\frac{10(11)(21)}{6} = 385.

Questions and Answers (Board Exam)

Q1. Define Arithmetic Progression.

Answer: A sequence where the difference between consecutive terms is constant is called an Arithmetic Progression.


Q2. What is the relation between A.M. and G.M.?

Answer: For any two positive real numbers, Arithmetic Mean \ge Geometric Mean (AGA \ge G).


Q3. Write the formula for sum of infinite G.P.

Answer: S=a1rS_\infty = \frac{a}{1-r}, valid only when r<1|r| < 1.


Q4. What is the sum of first nn natural numbers?

Answer: n(n+1)2\frac{n(n+1)}{2}.


Q5. If a,b,ca, b, c are in G.P., write the condition.

Answer: b2=acb^2 = ac or ba=cb\frac{b}{a} = \frac{c}{b}.