Quick Recap — Separable & Homogeneous

  • Homogeneous dydx=F(yx)\tfrac{dy}{dx}=F\big(\tfrac yx\big): substitute y=vxy=vx, so dydx=v+xdvdx\tfrac{dy}{dx}=v+x\tfrac{dv}{dx}.
  • Formation: eliminate the arbitrary constants by differentiating as many times as there are constants.
  • dydx=xyx2+y2=C\tfrac{dy}{dx}=-\tfrac xy\Rightarrow x^2+y^2=C (circles); dydx=yxy=Cx\tfrac{dy}{dx}=\tfrac yx\Rightarrow y=Cx (lines through origin).
  • Apply the initial condition only after integrating.