JEE / JEE Main 2027 / Math / Differential Equations Section 4 of 6 40 min read Medium Practice — Set 2 Quick Recap — Linear Differential Equations Standard form: dydx+P(x)y=Q(x)\tfrac{dy}{dx}+P(x)y=Q(x)dxdy+P(x)y=Q(x). Integrating factor: IF=e∫P dx\mathrm{IF}=e^{\int P\,dx}IF=e∫Pdx. Solution: y⋅IF=∫Q⋅IF dx+Cy\cdot\mathrm{IF}=\displaystyle\int Q\cdot\mathrm{IF}\,dx+Cy⋅IF=∫Q⋅IFdx+C. If Q=0Q=0Q=0, the equation reduces to y=Ce−∫P dxy=Ce^{-\int P\,dx}y=Ce−∫Pdx. Ready to test your knowledge? Take a quick interactive quiz on this topic — free, works without login. Start Quiz Next: Hard Practice — Advanced… ← Medium Practice — Set 1 Hard Practice — Advanced Set →