JEE / JEE Main 2027 / Math / Integral Calculus Section 2 of 6 30 min read Easy Practice — Set 2 Quick Recap — Definite Integrals Fundamental theorem: ∫abf(x) dx=F(b)−F(a)\displaystyle\int_a^b f(x)\,dx=F(b)-F(a)∫abf(x)dx=F(b)−F(a) where F′=fF'=fF′=f. ∫aaf=0\displaystyle\int_a^a f=0∫aaf=0 and ∫abf=−∫baf\displaystyle\int_a^b f=-\int_b^a f∫abf=−∫baf. Symmetry: ∫−aa(odd)=0\displaystyle\int_{-a}^{a}(\text{odd})=0∫−aa(odd)=0 and ∫−aa(even)=2∫0a\displaystyle\int_{-a}^{a}(\text{even})=2\int_0^a∫−aa(even)=2∫0a. Definite integral gives net signed area. Ready to test your knowledge? Take a quick interactive quiz on this topic — free, works without login. Start Quiz Next: Medium Practice — Set 1 ← Easy Practice — Set 1 Medium Practice — Set 1 →