JEE / JEE Main 2027 / Math / Integral Calculus Section 3 of 6 40 min read Medium Practice — Set 1 Quick Recap — Techniques of Integration Substitution: ∫f(g(x))g′(x) dx=∫f(u) du\int f(g(x))g'(x)\,dx=\int f(u)\,du∫f(g(x))g′(x)dx=∫f(u)du; e.g. ∫2xx2+1dx=ln(x2+1)\int\tfrac{2x}{x^2+1}dx=\ln(x^2+1)∫x2+12xdx=ln(x2+1). By parts: ∫u dv=uv−∫v du\int u\,dv=uv-\int v\,du∫udv=uv−∫vdu; ILATE order for choosing uuu. Standard: ∫tanx dx=ln∣secx∣\int\tan x\,dx=\ln|\sec x|∫tanxdx=ln∣secx∣, ∫cotx dx=ln∣sinx∣\int\cot x\,dx=\ln|\sin x|∫cotxdx=ln∣sinx∣. ∫dxx2+a2=1atan−1xa\int\tfrac{dx}{x^2+a^2}=\tfrac1a\tan^{-1}\tfrac xa∫x2+a2dx=a1tan−1ax, ∫dxa2−x2=sin−1xa\int\tfrac{dx}{\sqrt{a^2-x^2}}=\sin^{-1}\tfrac xa∫a2−x2dx=sin−1ax. Ready to test your knowledge? Take a quick interactive quiz on this topic — free, works without login. Start Quiz Next: Medium Practice — Set 2 ← Easy Practice — Set 2 Medium Practice — Set 2 →