Quick Recap — AP Sums & Means

  • Sn=n2(2a+(n1)d)S_n=\tfrac n2\big(2a+(n-1)d\big); nth term from sums: an=SnSn1a_n=S_n-S_{n-1}.
  • Inserting kk AMs between aa and bb: common difference d=bak+1d=\dfrac{b-a}{k+1}.
  • n=n(n+1)2\sum n=\tfrac{n(n+1)}{2}, sum of first nn evens =n(n+1)=n(n+1).
  • Three numbers in AP: take them ad,a,a+da-d,\,a,\,a+d.