JEE / JEE Main 2027 / Math / Sequences and Series Section 3 of 6 40 min read Medium Practice — Set 1 Quick Recap — AP Sums & Means Sn=n2(2a+(n−1)d)S_n=\tfrac n2\big(2a+(n-1)d\big)Sn=2n(2a+(n−1)d); nth term from sums: an=Sn−Sn−1a_n=S_n-S_{n-1}an=Sn−Sn−1. Inserting kkk AMs between aaa and bbb: common difference d=b−ak+1d=\dfrac{b-a}{k+1}d=k+1b−a. ∑n=n(n+1)2\sum n=\tfrac{n(n+1)}{2}∑n=2n(n+1), sum of first nnn evens =n(n+1)=n(n+1)=n(n+1). Three numbers in AP: take them a−d, a, a+da-d,\,a,\,a+da−d,a,a+d. Ready to test your knowledge? Take a quick interactive quiz on this topic — free, works without login. Start Quiz Next: Medium Practice — Set 2 ← Easy Practice — Set 2 Medium Practice — Set 2 →