JEE / JEE Main 2027 / Math / Trigonometry Section 4 of 6 40 min read Medium Practice — Set 2 Quick Recap — Inverse Trig & Triangles Principal ranges: sin−1x∈[−π2,π2]\sin^{-1}x\in[-\tfrac{\pi}{2},\tfrac{\pi}{2}]sin−1x∈[−2π,2π], cos−1x∈[0,π]\cos^{-1}x\in[0,\pi]cos−1x∈[0,π], tan−1x∈(−π2,π2)\tan^{-1}x\in(-\tfrac{\pi}{2},\tfrac{\pi}{2})tan−1x∈(−2π,2π). sin−1x+cos−1x=π2\sin^{-1}x+\cos^{-1}x=\tfrac{\pi}{2}sin−1x+cos−1x=2π; tan−1x+cot−1x=π2\tan^{-1}x+\cot^{-1}x=\tfrac{\pi}{2}tan−1x+cot−1x=2π. Sine rule: asinA=bsinB=csinC=2R\tfrac{a}{\sin A}=\tfrac{b}{\sin B}=\tfrac{c}{\sin C}=2RsinAa=sinBb=sinCc=2R; cosine rule: a2=b2+c2−2bccosAa^2=b^2+c^2-2bc\cos Aa2=b2+c2−2bccosA. Area of a triangle =12absinC=\tfrac12ab\sin C=21absinC; in any triangle A+B+C=πA+B+C=\piA+B+C=π. Ready to test your knowledge? Take a quick interactive quiz on this topic — free, works without login. Start Quiz Next: Hard Practice — Advanced… ← Medium Practice — Set 1 Hard Practice — Advanced Set →