JEE / JEE Main 2027 / Math / Trigonometry Section 3 of 6 40 min read Medium Practice — Set 1 Quick Recap — Values, Equations & Extremes sin75∘=3+122\sin75^\circ=\tfrac{\sqrt3+1}{2\sqrt2}sin75∘=223+1, cos75∘=3−122\cos75^\circ=\tfrac{\sqrt3-1}{2\sqrt2}cos75∘=223−1, tan75∘=2+3\tan75^\circ=2+\sqrt3tan75∘=2+3, tan15∘=2−3\tan15^\circ=2-\sqrt3tan15∘=2−3. General solutions: sinθ=0⇒θ=nπ\sin\theta=0\Rightarrow\theta=n\pisinθ=0⇒θ=nπ; cosθ=0⇒θ=(2n+1)π2\cos\theta=0\Rightarrow\theta=(2n+1)\tfrac{\pi}{2}cosθ=0⇒θ=(2n+1)2π; tanθ=tanα⇒θ=nπ+α\tan\theta=\tan\alpha\Rightarrow\theta=n\pi+\alphatanθ=tanα⇒θ=nπ+α. Range of asinθ+bcosθa\sin\theta+b\cos\thetaasinθ+bcosθ is [−a2+b2, a2+b2]\big[-\sqrt{a^2+b^2},\ \sqrt{a^2+b^2}\big][−a2+b2, a2+b2]. sin18∘=5−14\sin18^\circ=\tfrac{\sqrt5-1}{4}sin18∘=45−1, cos36∘=5+14\cos36^\circ=\tfrac{\sqrt5+1}{4}cos36∘=45+1. Ready to test your knowledge? Take a quick interactive quiz on this topic — free, works without login. Start Quiz Next: Medium Practice — Set 2 ← Easy Practice — Set 2 Medium Practice — Set 2 →