Quick Recap — Elasticity & Fluid Statics

  • Elasticity: stress =FA=\dfrac{F}{A}, strain =ΔLL=\dfrac{\Delta L}{L}, Young's modulus Y=FLA ΔLY=\dfrac{FL}{A\,\Delta L}; elongation ΔL=FLAY\Delta L=\dfrac{FL}{AY} (so ΔL∝L\Delta L\propto L and ∝1r2\propto\dfrac{1}{r^2}).
  • Energy: elastic PE =12F ΔL=12×=\tfrac12 F\,\Delta L=\tfrac12\timesstress×\timesstrain×\timesvolume. Thermal stress (clamped rod) =Yα ΔT=Y\alpha\,\Delta T.
  • Bulk modulus: B=−ΔPΔV/VB=-\dfrac{\Delta P}{\Delta V/V}; compressibility =1B=\dfrac1B; maximum self-supported length =σbreakρg=\dfrac{\sigma_{break}}{\rho g}.
  • Pressure: P=P0+ρghP=P_0+\rho g h (depends only on depth). Pascal / hydraulics: F1A1=F2A2\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}.
  • Buoyancy: a floating body has submerged volumetotal=ρbodyρfluid\dfrac{\text{submerged volume}}{\text{total}}=\dfrac{\rho_{body}}{\rho_{fluid}}; apparent weight == weight −- upthrust.

Worked mini-example. A steel wire (Y=2×1011Y=2\times10^{11} Pa, L=2L=2 m, A=1A=1 mm2^2) under a 100100 N load stretches by ΔL=FLAY=100×2(10−6)(2×1011)=10−3\Delta L=\dfrac{FL}{AY}=\dfrac{100\times2}{(10^{-6})(2\times10^{11})}=10^{-3} m =1=1 mm.