Quick Recap — First Law & Processes

  • First law: Q=ΔU+WQ=\Delta U+W, where W=∫P dVW=\int P\,dV is the work done by the gas. Internal energy of an ideal gas depends only on temperature: ΔU=nCVΔT\Delta U=nC_V\Delta T.
  • Process work: isochoric W=0W=0; isobaric W=P ΔV=nR ΔTW=P\,\Delta V=nR\,\Delta T; isothermal W=nRTln⁡V2V1W=nRT\ln\dfrac{V_2}{V_1}; adiabatic Q=0Q=0 so ΔU=−W\Delta U=-W.
  • Molar heats: CP−CV=RC_P-C_V=R, γ=CPCV\gamma=\dfrac{C_P}{C_V}, CV=Rγ−1C_V=\dfrac{R}{\gamma-1}. Monatomic γ=53\gamma=\tfrac53, diatomic γ=75\gamma=\tfrac75.
  • Adiabatic: PVγ=PV^\gamma= const and TVγ−1=TV^{\gamma-1}= const; on a PP–VV diagram an adiabat is steeper than an isotherm.
  • Cyclic process: ΔU=0\Delta U=0, so Q=W=Q=W= area enclosed (positive if clockwise).

Worked mini-example. 100 J of heat is supplied to a gas that does 40 J of work. By the first law ΔU=Q−W=100−40=60\Delta U=Q-W=100-40=60 J — its temperature rises.