Chapter Summary: Trigonometric Equations

  • Principal Solutions: These are the solutions to a trigonometric equation that lie in the interval [0,2π)[0, 2\pi).

  • General Solutions: These expressions give all possible solutions. The main formulas are:

    • For sinx=sinα    x=nπ+(1)nα\sin x = \sin \alpha \implies x = n\pi + (-1)^n \alpha
    • For cosx=cosα    x=2nπ±α\cos x = \cos \alpha \implies x = 2n\pi \pm \alpha
    • For tanx=tanα    x=nπ+α\tan x = \tan \alpha \implies x = n\pi + \alpha
    • For sin2x=sin2α\sin^2x = \sin^2\alpha, cos2x=cos2α\cos^2x = \cos^2\alpha, or tan2x=tan2α\tan^2x = \tan^2\alpha, the solution is x=nπ±αx = n\pi \pm \alpha.
  • Solving Methods: Common strategies include:

    1. Reducing the equation to a quadratic form (e.g., in sinx\sin x).
    2. Solving equations of the type asinx+bcosx=ca\sin x + b\cos x = c by dividing by a2+b2\sqrt{a^2+b^2}.
    3. Using sum-to-product and product-to-sum identities to factorize or simplify.
    4. Squaring both sides (requires checking for extraneous roots).

🎯 Strategic Tips for JEE Main & Advanced

  • Always Check the Domain: This is the most common trap. Before finalizing your solutions, check if any of them make terms in the original equation undefined (e.g., a denominator becoming zero, or tanx\tan x and secx\sec x being undefined for x=(2n+1)π/2x=(2n+1)\pi/2).

  • Don't Cancel Terms Blindly: Never cancel a common factor like sinx\sin x from both sides of an equation. This will cause you to lose solutions. Instead, bring all terms to one side and factor it out. For example, solve sinx=sinxcosx\sin x = \sin x \cos x as sinx(1cosx)=0\sin x (1-\cos x) = 0, which gives sinx=0\sin x = 0 or cosx=1\cos x = 1.

  • Squaring Can Add Fake Roots: When you square both sides of an equation, you may introduce extraneous solutions. It is absolutely essential to substitute all your potential solutions back into the original equation to verify them.

  • Master the asinx+bcosx=ca\sin x + b\cos x = c Form: This is a very high-yield topic. Be extremely comfortable with the method of dividing by a2+b2\sqrt{a^2+b^2} and converting the expression to a single sine or cosine function.

  • Use Graphs for Number of Solutions: If a question asks for the number of solutions in a given interval (and not the solutions themselves), often the quickest and safest method is to sketch the graphs of the LHS and RHS of the equation and count their points of intersection.