JEE / JEE Main 2027 / Chemistry / Atomic Structure Section 3 of 5 40 min read Medium Practice — Set 1 Quick Recap — Bohr, Spectra & Configuration Calculations En=−13.6 Z2n2E_n=-\dfrac{13.6\,Z^2}{n^2}En=−n213.6Z2 eV; rn=0.529n2Zr_n=0.529\dfrac{n^2}{Z}rn=0.529Zn2 Å; transition energy =Ehigh−Elow=E_{high}-E_{low}=Ehigh−Elow. Rydberg: 1λ=RHZ2 (1n12−1n22)\dfrac{1}{\lambda}=R_H Z^2\!\left(\dfrac{1}{n_1^2}-\dfrac{1}{n_2^2}\right)λ1=RHZ2(n121−n221); spectral lines from level n=n(n−1)2n=\dfrac{n(n-1)}{2}n=2n(n−1). Photon: E(eV)=1240λ(nm)E(\text{eV})=\dfrac{1240}{\lambda(\text{nm})}E(eV)=λ(nm)1240; de Broglie: λ=hmv\lambda=\dfrac{h}{mv}λ=mvh. Nodes: angular =l=l=l, total =n−1=n-1=n−1. Ready to test your knowledge? Take a quick interactive quiz on this topic — free, works without login. Start Quiz Next: Medium Practice — Set 2 ← Easy Practice — Set 2 Medium Practice — Set 2 →