JEE / JEE Main 2027 / Math / Complex Numbers and Quadratic Equations Section 2 of 6 30 min read Easy Practice — Set 2 Quick Recap — Quadratic Equations (Basics) For ax2+bx+c=0ax^2+bx+c=0ax2+bx+c=0: sum of roots =−ba=-\tfrac ba=−ab, product =ca=\tfrac ca=ac. Discriminant D=b2−4acD=b^2-4acD=b2−4ac: D>0D>0D>0 real distinct, D=0D=0D=0 real equal, D<0D<0D<0 complex conjugate. Roots: x=−b±D2ax=\dfrac{-b\pm\sqrt{D}}{2a}x=2a−b±D. A quadratic with roots α,β\alpha,\betaα,β is x2−(α+β)x+αβ=0x^2-(\alpha+\beta)x+\alpha\beta=0x2−(α+β)x+αβ=0. Ready to test your knowledge? Take a quick interactive quiz on this topic — free, works without login. Start Quiz Next: Medium Practice — Set 1 ← Easy Practice — Set 1 Medium Practice — Set 1 →