Quick Recap — Advanced Magnetism (Multi-step)

  • Charged particle relations: r=mvqB=2mKqB=2mqVqBr=\dfrac{mv}{qB}=\dfrac{\sqrt{2mK}}{qB}=\dfrac{\sqrt{2mqV}}{qB}. So for equal KE, rmqr\propto\dfrac{\sqrt m}{q}; for equal accelerating voltage, rm/q1r\propto\dfrac{\sqrt{m/q}}{1}.
  • Helix: pitch =vT=(vcosθ)2πmqB=v_\parallel T=(v\cos\theta)\dfrac{2\pi m}{qB}. Cyclotron max energy: E=q2B2R22mE=\dfrac{q^2B^2R^2}{2m}.
  • Geometry: field at the centre of a square loop of side aa is 22μ0Iπa\dfrac{2\sqrt2\,\mu_0 I}{\pi a}; a rotating charge QQ (radius RR, angular speed ω\omega) has moment QωR22\dfrac{Q\omega R^2}{2}.
  • Meter conversions: ammeter shunt S=IgGIIgS=\dfrac{I_g G}{I-I_g}; voltmeter series R=VIgGR=\dfrac{V}{I_g}-G.
  • Earth: B=BH2+BV2=BHcosδB=\sqrt{B_H^2+B_V^2}=\dfrac{B_H}{\cos\delta}.

Worked mini-example. A proton and an alpha particle accelerated through the same potential enter the same field. r=2mqVqBmqr=\dfrac{\sqrt{2mqV}}{qB}\propto\sqrt{\dfrac{m}{q}}; with mαqα=42=2\dfrac{m_\alpha}{q_\alpha}=\dfrac{4}{2}=2 times that of the proton, rα=2rpr_\alpha=\sqrt2\,r_p.