Quick Recap — Magnetic Fields from Currents

  • Sources (μ0=4π×107\mu_0=4\pi\times10^{-7}): long straight wire B=μ0I2πrB=\dfrac{\mu_0 I}{2\pi r}; loop centre B=μ0NI2RB=\dfrac{\mu_0 N I}{2R}; solenoid B=μ0nIB=\mu_0 n I; arc of angle θ\theta at its centre B=μ0Iθ4πRB=\dfrac{\mu_0 I\theta}{4\pi R} (semicircle μ0I4R\dfrac{\mu_0 I}{4R}).
  • Ampere's law: Bdl=μ0Ienc\oint \vec B\cdot d\vec l=\mu_0 I_{enc}.
  • Charge in a field: F=qv×B\vec F=q\vec v\times\vec B — always perpendicular to v\vec v, so it does no work (speed and KE stay constant). Circular motion: r=mvqBr=\dfrac{mv}{qB}, period T=2πmqBT=\dfrac{2\pi m}{qB} (independent of vv), frequency f=qB2πmf=\dfrac{qB}{2\pi m}.
  • Velocity selector: undeflected when qE=qvBv=EBqE=qvB\Rightarrow v=\dfrac{E}{B}.

Worked mini-example. A proton (m=1.67×1027m=1.67\times10^{-27} kg) at v=106v=10^6 m/s in B=0.5B=0.5 T moves on a circle of radius r=mvqB=(1.67×1027)(106)(1.6×1019)(0.5)2.1r=\dfrac{mv}{qB}=\dfrac{(1.67\times10^{-27})(10^6)}{(1.6\times10^{-19})(0.5)}\approx2.1 cm.