Quick Recap — Advanced Optics (Multi-step)

  • Silvered lens = equivalent mirror: power P=2Plens+PmirrorP=2P_{lens}+P_{mirror}, so 1F=2flens+1fmirror\dfrac{1}{F}=\dfrac{2}{f_{lens}}+\dfrac{1}{f_{mirror}}; then use the mirror formula.
  • Cut lenses: cut along the axis f\Rightarrow f unchanged; cut across the axis (into two plano-convex) f\Rightarrow f doubles for each half.
  • Lenses a distance dd apart: P=P1+P2dP1P2P=P_1+P_2-dP_1P_2. Achromatic doublet: ω1f1+ω2f2=0\dfrac{\omega_1}{f_1}+\dfrac{\omega_2}{f_2}=0.
  • YDSE slab shift: Δy=(n1)tDd\Delta y=\dfrac{(n-1)tD}{d}. Layered apparent depth: tini\sum\dfrac{t_i}{n_i}.
  • Two-source contrast: with amplitude ratio r=I1/I2r=\sqrt{I_1/I_2}, ImaxImin=(r+1r1)2\dfrac{I_{max}}{I_{min}}=\left(\dfrac{r+1}{r-1}\right)^2; fringe visibility =2r1+r2=\dfrac{2r}{1+r^2}.

Worked mini-example. A plano-convex lens (n=1.5n=1.5, R=20R=20 cm, so flens=Rn1=40f_{lens}=\tfrac{R}{n-1}=40 cm) silvered on its plane face has 1F=240=120\dfrac{1}{F}=\dfrac{2}{40}=\dfrac{1}{20}, i.e. it acts as a concave mirror of focal length 20 cm. An object 30 cm away then images at 1v=120130=160\dfrac{1}{v}=\dfrac{1}{-20}-\dfrac{1}{-30}=-\dfrac{1}{60}, v=60v=-60 cm (real, m=2m=-2).