Continuity and Differentiability Concepts

1. Continuity at an interior point

A function ff is continuous at x=cx=c if limxcf(x)=limxc+f(x)=f(c).\lim_{x \to c^-} f(x) = \lim_{x \to c^+} f(x) = f(c). In words, the left-hand limit, right-hand limit, and actual function value must all exist and be equal.

2. Continuity on a closed interval

If the function is defined on [a,b][a,b], then continuity at the endpoints is checked using one-sided limits: limxa+f(x)=f(a),limxbf(x)=f(b).\lim_{x \to a^+} f(x)=f(a), \qquad \lim_{x \to b^-} f(x)=f(b).

3. Algebra of Continuous Functions

If ff and gg are continuous at cc, then f+gf+g, fgf-g, and fgf \cdot g are continuous at cc. Also, fg\frac{f}{g} is continuous at cc provided g(c)0g(c) \neq 0.

4. Composite Functions

If gg is continuous at cc and ff is continuous at g(c)g(c), then (fg)(x)=f(g(x))(f \circ g)(x)=f(g(x)) is continuous at cc.

5. Differentiability at a point

A function ff is differentiable at x=cx=c if f(c)=limh0f(c+h)f(c)hf'(c)=\lim_{h \to 0} \frac{f(c+h)-f(c)}{h} exists as a finite real number.

6. LHD and RHD test for differentiability

For differentiability at x=cx=c, we must have limh0f(c+h)f(c)h=limh0+f(c+h)f(c)h.\lim_{h \to 0^-} \frac{f(c+h)-f(c)}{h} = \lim_{h \to 0^+} \frac{f(c+h)-f(c)}{h}.

7. Core theorem

Every differentiable function is continuous, but every continuous function need not be differentiable. The standard example is f(x)=x,f(x)=|x|, which is continuous at x=0x=0 but not differentiable there because the slopes from the left and right are different.

8. Where non-differentiability usually occurs

sharp corners, cusps, vertical tangents, jump discontinuities, and oscillatory behavior near a point.

Rules of Differentiation

Let u=u(x)u=u(x) and v=v(x)v=v(x) be differentiable functions.

1. Sum and Difference Rule

ddx(u±v)=dudx±dvdx\frac{d}{dx}(u \pm v)=\frac{du}{dx} \pm \frac{dv}{dx}

2. Product Rule (Leibnitz Rule)

ddx(uv)=udvdx+vdudx\frac{d}{dx}(uv)=u\frac{dv}{dx}+v\frac{du}{dx}

3. Quotient Rule

ddx(uv)=vdudxudvdxv2,v0\frac{d}{dx}\left(\frac{u}{v}\right)=\frac{v\frac{du}{dx}-u\frac{dv}{dx}}{v^2}, \qquad v \neq 0

4. Chain Rule

If y=f(u)y=f(u) and u=g(x)u=g(x), then dydx=dydududx.\frac{dy}{dx}=\frac{dy}{du}\cdot\frac{du}{dx}. This is the backbone of almost every advanced derivative question.

5. Repeated Chain Rule

For a composition like y=f(g(h(x)))y=f(g(h(x))), dydx=f(g(h(x)))g(h(x))h(x).\frac{dy}{dx}=f'(g(h(x)))\cdot g'(h(x))\cdot h'(x). Important reminder: In questions involving inverse trigonometric, exponential, logarithmic, or parametric forms, the chain rule is almost always used somewhere, even if it is hidden.

Master List of Standard Derivatives

1.Algebraic & Trigonometric

  • ddx(xn)=nxn1\frac{d}{dx}(x^n)=n x^{n-1}
  • ddx(sinx)=cosx\frac{d}{dx}(\sin x)=\cos x
  • ddx(cosx)=sinx\frac{d}{dx}(\cos x)=-\sin x
  • ddx(tanx)=sec2x\frac{d}{dx}(\tan x)=\sec^2 x
  • ddx(cotx)=csc2x\frac{d}{dx}(\cot x)=-\csc^2 x
  • ddx(secx)=secxtanx\frac{d}{dx}(\sec x)=\sec x\tan x
  • ddx(cscx)=cscxcotx\frac{d}{dx}(\csc x)=-\csc x\cot x

2. Inverse Trigonometric

  • ddx(sin1x)=11x2,1<x<1\frac{d}{dx}(\sin^{-1}x)=\frac{1}{\sqrt{1-x^2}}, \quad -1<x<1
  • ddx(cos1x)=11x2,1<x<1\frac{d}{dx}(\cos^{-1}x)=\frac{-1}{\sqrt{1-x^2}}, \quad -1<x<1
  • ddx(tan1x)=11+x2\frac{d}{dx}(\tan^{-1}x)=\frac{1}{1+x^2}
  • ddx(cot1x)=11+x2\frac{d}{dx}(\cot^{-1}x)=\frac{-1}{1+x^2}
  • ddx(sec1x)=1xx21,x>1\frac{d}{dx}(\sec^{-1}x)=\frac{1}{|x|\sqrt{x^2-1}}, \quad |x|>1
  • ddx(csc1x)=1xx21,x>1\frac{d}{dx}(\csc^{-1}x)=\frac{-1}{|x|\sqrt{x^2-1}}, \quad |x|>1

3. Exponential & Logarithmic

  • ddx(ex)=ex\frac{d}{dx}(e^x)=e^x
  • ddx(ax)=axlna,a>0,a1\frac{d}{dx}(a^x)=a^x\ln a, \quad a>0, a\neq 1
  • ddx(lnx)=1x,x>0\frac{d}{dx}(\ln x)=\frac{1}{x}, \quad x>0
  • ddx(logax)=1xlna,a>0,a1\frac{d}{dx}(\log_a x)=\frac{1}{x\ln a}, \quad a>0, a\neq 1

4. Useful composite forms to remember

  • ddx(eu)=euu\frac{d}{dx}(e^{u})=e^{u}\cdot u'
  • ddx(lnu)=uu\frac{d}{dx}(\ln u)=\frac{u'}{u}
  • ddx(au)=aulnau\frac{d}{dx}(a^{u})=a^{u}\ln a \cdot u'
  • ddx(sin1u)=u1u2\frac{d}{dx}(\sin^{-1}u)=\frac{u'}{\sqrt{1-u^2}}
  • ddx(tan1u)=u1+u2\frac{d}{dx}(\tan^{-1}u)=\frac{u'}{1+u^2}

Advanced Differentiation Techniques

1. Implicit Differentiation

If a relation is given as F(x,y)=0,F(x,y)=0, then differentiate both sides with respect to xx. Every time yy is differentiated, multiply by dydx\frac{dy}{dx} due to the chain rule. For example, ddx(y2)=2ydydx,ddx(siny)=cosydydx.\frac{d}{dx}(y^2)=2y\frac{dy}{dx}, \qquad \frac{d}{dx}(\sin y)=\cos y\frac{dy}{dx}. After differentiation, collect all dydx\frac{dy}{dx} terms on one side and solve.

2. Logarithmic Properties

ln(xy)=lnx+lny,\ln(xy)=\ln x+\ln y, ln(xy)=lnxlny,\ln\left(\frac{x}{y}\right)=\ln x-\ln y, ln(xn)=nlnx,\ln(x^n)=n\ln x, logax=lnxlna.\log_a x = \frac{\ln x}{\ln a}.

3. Logarithmic Differentiation

This is especially useful when the function is of the form y=u(x)v(x)y=u(x)^{v(x)} or is a complicated product/quotient with powers. The method is:

  1. Take natural logarithm on both sides.
  2. Simplify using logarithmic laws.
  3. Differentiate implicitly.
  4. Replace yy by the original expression in the final answer.

Important warning: ln(u+v)lnu+lnv.\ln(u+v) \neq \ln u + \ln v. So logarithmic differentiation cannot be applied directly to a sum.

4. Parametric Differentiation

If x=f(t),y=g(t),x=f(t), \qquad y=g(t), then dydx=dy/dtdx/dt,dxdt0.\frac{dy}{dx}=\frac{dy/dt}{dx/dt}, \qquad \frac{dx}{dt} \neq 0.

5. Second Order Derivative in Parametric Form

d2ydx2=ddt(dydx)dtdx.\frac{d^2y}{dx^2}=\frac{d}{dt}\left(\frac{dy}{dx}\right)\cdot \frac{dt}{dx}. This is the correct formula. It is not equal to d2y/dt2d2x/dt2\frac{d^2y/dt^2}{d^2x/dt^2}.

6. Differentiation with respect to another function

If u=u(x)u=u(x) and v=v(x)v=v(x), then dudv=du/dxdv/dx,dvdx0.\frac{du}{dv}=\frac{du/dx}{dv/dx}, \qquad \frac{dv}{dx} \neq 0.

Exam Tips for Board Exams

Continuity proofs

Always write LHL, RHL, and function value separately. Then conclude continuity by showing LHL=RHL=f(c).LHL = RHL = f(c).

Differentiability proofs

Write the definitions of LHD and RHD clearly before evaluating them. This presentation is often rewarded in board marking schemes.

Implicit differentiation

Start with the sentence: Differentiating both sides with respect to xx. Then show the chain rule properly for terms containing yy.

Logarithmic differentiation

If the function is a sum like xx+(sinx)xx^x + (\sin x)^x, do not take logarithm of the whole expression. Split it into separate parts first.

Second derivative proofs

When asked to prove expressions such as (1x2)yxy=2,(1-x^2)y'' - xy' = 2, it is often easier to first simplify or rearrange the equation involving yy' before differentiating again.

Substitute back in final answers

After logarithmic differentiation, never leave the result in terms of yy if the original question asked for derivative in terms of xx.

Write domain restrictions when needed

For example, while differentiating lnx\ln x, write that x>0x>0; for inverse trigonometric functions, note their valid intervals when relevant.

Be careful with notation

yy', dydx\frac{dy}{dx}, yy'', and d2ydx2\frac{d^2y}{dx^2} should be used neatly and consistently.

Exam Tips for JEE Main & Advanced

Spot non-differentiability quickly

For g(x)|g(x)|, likely trouble occurs where g(x)=0g(x)=0. If the sign changes there, the graph usually has a corner. For sums of modulus terms, check all such points.

Max/Min functions

For f(x)=max(g(x),h(x))orf(x)=min(g(x),h(x)),f(x)=\max(g(x),h(x)) \quad \text{or} \quad f(x)=\min(g(x),h(x)), the likely critical points are where g(x)=h(x)g(x)=h(x).

Inverse trigonometric simplification

If expressions like 2x1+x2,1x21+x2,2x1x2,3xx313x2\frac{2x}{1+x^2}, \quad \frac{1-x^2}{1+x^2}, \quad \frac{2x}{1-x^2}, \quad \frac{3x-x^3}{1-3x^2} appear inside inverse trigonometric functions, look for substitutions such as x=tanθx=\tan\theta and use double-angle or triple-angle identities.

Parametric second derivative trap

Memorize the correct formula: d2ydx2=ddt(dydx)dtdx.\frac{d^2y}{dx^2}=\frac{d}{dt}\left(\frac{dy}{dx}\right)\cdot\frac{dt}{dx}. Never replace it by a naive ratio of second derivatives with respect to tt.

Infinite nested structures

If the expression repeats forever, assign the repeating block to a variable and convert the infinite form into an algebraic or implicit equation.

Oscillatory functions near zero

For functions containing sin(1/x)\sin(1/x) or cos(1/x)\cos(1/x), use squeeze theorem ideas for continuity and the first-principle derivative for differentiability.

Functional equations

When a question involves something like f(x+y)=f(x)+f(y)+xyf(x+y)=f(x)+f(y)+xy or f(x+y)=f(x)f(y),f(x+y)=f(x)f(y), substitute y=hy=h and use first principles.

Compositions

In repeated compositions like f(f(f(x)))f(f(f(x))), apply the chain rule layer by layer. Missing even one factor is a common JEE mistake.

Time-saving principle

Before differentiating a long expression directly, first try to simplify it using identities, factorization, substitution, or logarithms. In competitive exams, simplification is often the real key step.