Chapter 5 at a Glance

Continuity

ff is continuous at a domain point cc when limxcf(x)=f(c)\lim_{x \to c} f(x) = f(c) — left limit, right limit and value all present and equal. Sums, differences, products and quotients (denominator nonzero) of continuous functions stay continuous, and so do composites; polynomials, rational functions, sin\sin, cos\cos and x\vert x \vert are continuous throughout their domains, while [x][x] jumps at every integer.

Continuous curve where limit equals value versus a jump discontinuity

Differentiability

f(c)=limh0f(c+h)f(c)hf'(c) = \lim_{h \to 0}\frac{f(c+h) - f(c)}{h}, when the limit exists. Every differentiable function is continuous; the converse failsx\vert x \vert has a corner at 00 (LHD 1-1, RHD +1+1).

Smooth curve with one tangent versus modulus corner with two slopes

The derivative table

f(x)f(x) f(x)f'(x) f(x)f(x) f(x)f'(x)
xnx^n nxn1nx^{n-1} sin1x\sin^{-1} x 11x2\frac{1}{\sqrt{1-x^2}}
sinx\sin x cosx\cos x cos1x\cos^{-1} x 11x2-\frac{1}{\sqrt{1-x^2}}
cosx\cos x sinx-\sin x tan1x\tan^{-1} x 11+x2\frac{1}{1+x^2}
tanx\tan x sec2x\sec^2 x exe^x exe^x
axa^x axlogaa^x\log a logx\log x 1x\frac{1}{x}

The techniques

Chain rule: ddxv(u(x))=v(u(x))u(x)\frac{d}{dx}v(u(x)) = v'(u(x))\,u'(x) — one factor per layer. Implicit: differentiate the relation; every yy triggers a dydx\frac{dy}{dx}. Logarithmic: for u(x)v(x)u(x)^{v(x)} (both positive where needed), logy=vlogu\log y = v\log u first. Parametric: dydx=dy/dtdx/dt\frac{dy}{dx} = \frac{dy/dt}{dx/dt} (with dxdt0\frac{dx}{dt} \neq 0). Second order: differentiate again; for relation proofs, clear radicals/denominators after the first round, then differentiate the cleaned equation.

Mistake checklist

  1. Forgetting the inner derivativeddxsin(x2)=2xcos(x2)\frac{d}{dx}\sin(x^2) = 2x\cos(x^2), never just cos(x2)\cos(x^2).
  2. Continuity at joints only — piecewise functions can misbehave only at their joints; test each joint's LHL, RHL and value separately.
  3. Differentiable needs continuous first — and xa\vert x - a \vert is the standing example that continuity alone is not enough.
  4. xxx^x is not xxx1x \cdot x^{x-1} — variable-to-variable powers demand logarithmic differentiation; keep the classification straight (xax^a: power rule; axa^x: axlogaa^x\log a).
  5. Parametric fractions the right way updy/dtdx/dt\frac{dy/dt}{dx/dt}, and the second derivative is not d2y/dt2d2x/dt2\frac{d^2y/dt^2}{d^2x/dt^2}.
  6. Simplify inverse-trig arguments first — the substitution dictionary (x=tanθx = \tan\theta, x=sinθx = \sin\theta, x=cosθx = \cos\theta) turns page-long quotient rules into one-liners.
  7. d2ydx2(dydx)2\frac{d^2y}{dx^2} \neq \left(\frac{dy}{dx}\right)^2 — the superscript counts repetitions, not powers.

The 15 questions below are a fast pass over the whole chapter at recall level. Each explanation names the section to revisit if it feels shaky.