JEE / JEE Main 2027 / Chemistry / Redox Reactions and Electrochemistry Section 5 of 5 55 min read Hard Practice — Advanced Set Quick Recap — Multi-step Electrochemistry (Hard) Ecell∘=Ecathode∘−Eanode∘E^\circ_{cell}=E^\circ_{cathode}-E^\circ_{anode}Ecell∘=Ecathode∘−Eanode∘; Nernst: E=E∘−0.059nlogQE=E^\circ-\dfrac{0.059}{n}\log QE=E∘−n0.059logQ; ΔG∘=−nFE∘\Delta G^\circ=-nFE^\circΔG∘=−nFE∘; logK=nE∘0.059\log K=\dfrac{nE^\circ}{0.059}logK=0.059nE∘. Faraday: m=MnFItm=\dfrac{M}{nF}Itm=nFMIt, Q=ItQ=ItQ=It; Λm=κ×1000C\Lambda_m=\dfrac{\kappa\times1000}{C}Λm=Cκ×1000, α=ΛmΛm∘\alpha=\dfrac{\Lambda_m}{\Lambda^\circ_m}α=Λm∘Λm. Watch the number of electrons (nnn) per ion and per gas molecule. Ready to test your knowledge? Take a quick interactive quiz on this topic — free, works without login. Start Quiz ← Medium Practice — Set 2