JEE / JEE Main 2027 / Chemistry / Solutions Section 3 of 5 40 min read Medium Practice — Set 1 Quick Recap — Concentration & Colligative Calculations M=nV(L)M=\dfrac{n}{V(L)}M=V(L)n, m=nkg solventm=\dfrac{n}{\text{kg solvent}}m=kg solventn; from mass %: M=10×%(w/w)×dmolar massM=\dfrac{10\times\%(w/w)\times d}{\text{molar mass}}M=molar mass10×%(w/w)×d. ΔTb=iKbm\Delta T_b=iK_b mΔTb=iKbm, ΔTf=iKfm\Delta T_f=iK_f mΔTf=iKfm, π=iMRT\pi=iMRTπ=iMRT (use Kb=0.52K_b=0.52Kb=0.52, Kf=1.86K_f=1.86Kf=1.86 for water; R=0.0821R=0.0821R=0.0821 L⋅\cdot⋅atm/mol⋅\cdot⋅K). Raoult: p=p∘xsolventp=p^\circ x_{solvent}p=p∘xsolvent; p∘−pp∘=xsolute\dfrac{p^\circ-p}{p^\circ}=x_{solute}p∘p∘−p=xsolute. More particles (larger iii) ⇒\Rightarrow⇒ larger colligative effect. Ready to test your knowledge? Take a quick interactive quiz on this topic — free, works without login. Start Quiz Next: Medium Practice — Set 2 ← Easy Practice — Set 2 Medium Practice — Set 2 →