JEE / JEE Main 2027 / Math / Vector Algebra Section 2 of 6 30 min read Easy Practice — Set 2 Quick Recap — Dot & Cross Products a⃗⋅b⃗=∣a⃗∣∣b⃗∣cosθ\vec a\cdot\vec b=|\vec a||\vec b|\cos\thetaa⋅b=∣a∣∣b∣cosθ (a scalar); ∣a⃗×b⃗∣=∣a⃗∣∣b⃗∣sinθ|\vec a\times\vec b|=|\vec a||\vec b|\sin\theta∣a×b∣=∣a∣∣b∣sinθ (a vector). a⃗⋅b⃗=0⇒\vec a\cdot\vec b=0\Rightarrowa⋅b=0⇒ perpendicular; a⃗×b⃗=0⃗⇒\vec a\times\vec b=\vec0\Rightarrowa×b=0⇒ parallel. Area: parallelogram =∣a⃗×b⃗∣=|\vec a\times\vec b|=∣a×b∣; triangle =12∣a⃗×b⃗∣=\tfrac12|\vec a\times\vec b|=21∣a×b∣. Scalar triple product [a⃗ b⃗ c⃗]=a⃗⋅(b⃗×c⃗)[\vec a\,\vec b\,\vec c]=\vec a\cdot(\vec b\times\vec c)[abc]=a⋅(b×c); zero ⇒\Rightarrow⇒ coplanar. Ready to test your knowledge? Take a quick interactive quiz on this topic — free, works without login. Start Quiz Next: Medium Practice — Set 1 ← Easy Practice — Set 1 Medium Practice — Set 1 →