JEE / JEE Main 2027 / Math / Vector Algebra Section 4 of 6 40 min read Medium Practice — Set 2 Quick Recap — Cross & Triple Products a⃗×b⃗\vec a\times\vec ba×b is perpendicular to both; ∣a⃗×b⃗∣=∣a⃗∣∣b⃗∣sinθ|\vec a\times\vec b|=|\vec a||\vec b|\sin\theta∣a×b∣=∣a∣∣b∣sinθ. Lagrange: ∣a⃗×b⃗∣2+(a⃗⋅b⃗)2=∣a⃗∣2∣b⃗∣2|\vec a\times\vec b|^2+(\vec a\cdot\vec b)^2=|\vec a|^2|\vec b|^2∣a×b∣2+(a⋅b)2=∣a∣2∣b∣2. Volume of a parallelepiped =∣[a⃗ b⃗ c⃗]∣=|[\vec a\,\vec b\,\vec c]|=∣[abc]∣; [a⃗ b⃗ c⃗]=[b⃗ c⃗ a⃗][\vec a\,\vec b\,\vec c]=[\vec b\,\vec c\,\vec a][abc]=[bca] (cyclic). Moment of a force: M⃗=r⃗×F⃗\vec M=\vec r\times\vec FM=r×F. Ready to test your knowledge? Take a quick interactive quiz on this topic — free, works without login. Start Quiz Next: Hard Practice — Advanced… ← Medium Practice — Set 1 Hard Practice — Advanced Set →