The Formula Marathon

This table contains every formula you need to master this chapter. Use this for your 'last-minute' revision before the exam!

Concept Formula Key Notes
Potential (Point Charge) V=14πϵ0QrV = \frac{1}{4\pi\epsilon_0} \frac{Q}{r} Scalar quantity; use sign of QQ
Potential (Dipole) V=14πϵ0pcosθr2V = \frac{1}{4\pi\epsilon_0} \frac{p \cos \theta}{r^2} p=q×2ap = q \times 2a; V=0V=0 at equatorial plane
Potential Energy (System) U=14πϵ0q1q2r12U = \frac{1}{4\pi\epsilon_0} \frac{q_1 q_2}{r_{12}} Work done in assembling the system
Dipole Energy in Field U=pE=pEcosθU = -\vec{p} \cdot \vec{E} = -pE \cos \theta Min at 00^{\circ} (stable); Max at 180180^{\circ} (unstable)
Field-Potential Relation E=dVdrE = -\frac{dV}{dr} Field points towards decreasing potential
Capacitance (General) C=QVC = \frac{Q}{V} SI Unit: Farad (F)
Parallel Plate Capacitor C=ϵ0AdC = \frac{\epsilon_0 A}{d} With dielectric: Cmed=KCvacC_{med} = K C_{vac}
Capacitors in Series 1Cs=1C1+1C2+\frac{1}{C_s} = \frac{1}{C_1} + \frac{1}{C_2} + \dots Charge QQ is same; Voltage VV divides
Capacitors in Parallel Cp=C1+C2+C_p = C_1 + C_2 + \dots Voltage VV is same; Charge QQ divides
Energy Stored U=12CV2=Q22CU = \frac{1}{2} CV^2 = \frac{Q^2}{2C} Stored in the electric field
Energy Density u=12ϵ0E2u = \frac{1}{2} \epsilon_0 E^2 Energy per unit volume
Common Potential V=C1V1+C2V2C1+C2V = \frac{C_1 V_1 + C_2 V_2}{C_1 + C_2} For connected capacitors
Energy Loss (Sharing) ΔU=C1C2(V1V2)22(C1+C2)\Delta U = \frac{C_1 C_2 (V_1 - V_2)^2}{2(C_1 + C_2)} Dissipated as heat in wires

Core Concepts Recap

  • Conservative Nature: The work done by an electrostatic field is independent of the path; it depends only on initial and final points.
  • Equipotential Surfaces: Surfaces where VV is constant. No work is done moving a charge on these. E\vec{E} is always perpendicular to these surfaces.
  • Conductor Properties: E=0E = 0 inside; Potential is constant throughout; Excess charge stays on the outer surface; E\vec{E} at surface is σ/ϵ0\sigma/\epsilon_0.
  • Dielectrics: These are insulators that polarize. Polarization reduces the internal field by factor KK, thus increasing capacitance.
  • Capacitance Factors: CC depends only on geometry (A,dA, d) and the medium (KK). It does NOT depend on QQ or VV.

🎯 Exam Success Guide

For Board Exams (CBSE/State):

  1. Standard Derivations: Always practice the derivation for Potential due to a Dipole, Capacitance of Parallel Plate (with and without dielectric), and Energy Stored in a capacitor. These are high-weightage 3 or 5-mark questions.
  2. Units Matter: Don't forget that 1 Farad1 \text{ Farad} is huge. Use 10610^{-6} for μF\mu F and 101210^{-12} for pFpF in numericals.
  3. Graphing: Be prepared to draw VV vs. rr and EE vs. rr on the same axes for a conducting shell.

For JEE Main & NEET:

  1. The Battery Scenario: Remember the 'Disconnected battery' (QQ constant) vs. 'Connected battery' (VV constant) logic for dielectric insertion. This is the most common competitive theme.
  2. Energy Loss Shortcut: Don't derive the redistribution energy every time. Memorize the ΔU\Delta U formula for sharing charges to save 2 minutes of calculation.
  3. Complex Circuits: Master the 'Successive Reduction' method and look for symmetry (Wheatstone Bridge) in capacitor networks.
  4. Variable Dielectric: For slabs of different thicknesses, use the series capacitor formula: dCeff=tiCi\frac{d}{C_{eff}} = \sum \frac{t_i}{C_i}.