What Does Probability Measure?

Probability is a number that measures how likely an event is to happen. It runs from 0 (the event cannot happen) to 1 (the event is certain). A probability of 12\dfrac12 means an even chance — as likely to happen as not.

In Class 9 you estimated probability by experiment (tossing a coin many times and counting). Here we compute the exact, theoretical probability by reasoning about the possible outcomes — no experiment needed.

Equally Likely Outcomes and the Formula

The key assumption is that the possible outcomes are equally likely — none is favoured over another. When you toss a fair coin, head and tail are equally likely; when you throw a fair die, the six faces 1,2,3,4,5,61,2,3,4,5,6 are equally likely.

For an event EE, the theoretical probability is P(E)=number of outcomes favourable to Etotal number of equally likely outcomes\boxed{P(E) = \dfrac{\text{number of outcomes favourable to } E}{\text{total number of equally likely outcomes}}}

How to use it: (1) list or count all equally likely outcomes (the sample space); (2) count how many are favourable to EE; (3) divide.

Key Point: Every probability is (favourable)/(total). The whole chapter is careful counting.

Two equally likely sample spaces: a coin showing its two outcomes head and tail, and a die showing its six outcomes 1 to 6.

Elementary Events

An elementary event is an event with exactly one outcome — for example, "getting a head" when tossing one coin, or "getting a 3" when throwing a die.

A neat fact ties them together:

The sum of the probabilities of all the elementary events of an experiment is 1.

For a die, P(1)+P(2)++P(6)=16×6=1P(1)+P(2)+\dots+P(6) = \dfrac16\times 6 = 1. For a coin, P(H)+P(T)=12+12=1P(H)+P(T)=\dfrac12+\dfrac12=1.

[Board Important] Because all outcomes together are certain, their probabilities must total 1 — a quick way to check your counting.

Solved Examples

Example 1: One coin

A fair coin is tossed once. Find the probability of getting a head.

Solution:

  1. Total equally likely outcomes: head, tail 2\Rightarrow 2.
  2. Favourable to "head": 11.
  3. P(head)=12P(\text{head}) = \dfrac12.

Final Answer: 12\dfrac12.

Takeaway: Favourable over total.

Example 2: One die

A fair die is thrown once. Find the probability of getting (i) a 4, (ii) an even number.

Solution:

  1. Total outcomes: 1,2,3,4,5,661,2,3,4,5,6 \Rightarrow 6.
  2. (i) Favourable to 4: just {4}\{4\}, so P=16P = \dfrac16.
  3. (ii) Even numbers {2,4,6}\{2,4,6\}: 33 favourable, so P=36=12P = \dfrac36 = \dfrac12.

Final Answer: (i) 16\dfrac16; (ii) 12\dfrac12.

Takeaway: Count the favourable outcomes carefully.

Example 3: A number greater than 4

A die is thrown. Find the probability of a number greater than 4.

Solution:

  1. Numbers greater than 4: {5,6}\{5,6\}, so 22 favourable.
  2. P=26=13P = \dfrac26 = \dfrac13.

Final Answer: 13\dfrac13.

Takeaway: "Greater than 4" does not include 4 itself.

Example 4: Elementary events sum to 1

A die is thrown. Verify that the probabilities of the six elementary events add to 1.

Solution:

  1. Each face has probability 16\dfrac16.
  2. Sum =6×16=1= 6\times\dfrac16 = 1.

Final Answer: The total is 1.

Takeaway: All elementary events together are certain, so their probabilities sum to 1.