The Chapter in One Idea

Everything here flows from one contrast:

Add a constant each step and you get an A.P.; multiply by a constant each step and you get a G.P. The general term records how many steps you took (arn1ar^{n-1} — one multiplication per step after the first), and the sum formula comes from the subtract-and-shift trick that cancels the middle.

Every formula below is that idea dressed for a different occasion.

Sequences, Series and the G.P. — Formula Card

  • Sequence: an arrangement of numbers by rule — formally a function on N\mathbb{N}; terms a1,a2,a_1, a_2, \ldots; general term ana_n. Rules: formula (an=2na_n = 2n), recurrence (Fibonacci an=an1+an2a_n = a_{n-1} + a_{n-2}), or words only (the primes).
  • Series: a1+a2+a_1 + a_2 + \cdots, compactly k=1nak\sum_{k=1}^n a_k — the indicated sum; its value is the "sum of the series."
  • G.P.: each term non-zero with ak+1ak=r\frac{a_{k+1}}{a_k} = r constant: a,ar,ar2,a, ar, ar^2, \ldots
  • General term: an=arn1a_n = ar^{n-1} — one rr fewer than the position.
  • Sum: Sn=a(rn1)r1=a(1rn)1rS_n = \frac{a(r^n - 1)}{r - 1} = \frac{a(1 - r^n)}{1 - r} for r1r \ne 1; Sn=naS_n = na when r=1r = 1.
  • Two-condition problems: DIVIDE the term equations (a6a3=r3\frac{a_6}{a_3} = r^3) — never subtract.
  • Symmetric terms: three as ar,a,ar\frac{a}{r}, a, ar (product a3a^3); the equal-spacing fact — the pp-th, qq-th, rr-th terms at equal gaps stay in G.P.
  • Repdigits: 7+77+=79[10(10n1)9n]7 + 77 + \cdots = \frac{7}{9}\left[\frac{10(10^n-1)}{9} - n\right] — factor the digit, write 10k110^k - 1, sum.

Means — Formula Card

  • Geometric mean: G=abG = \sqrt{ab} for positive a,ba, b; then a,G,ba, G, b is a G.P.
  • Inserting nn G.M.s: bb becomes the (n+2)(n+2)-th term, so r=(ba)1n+1r = \left(\frac{b}{a}\right)^{\frac{1}{n+1}} and Gk=arkG_k = ar^k.
  • A.M.-G.M.: a+b2ab\frac{a+b}{2} \ge \sqrt{ab}, since AG=(ab)220A - G = \frac{(\sqrt{a}-\sqrt{b})^2}{2} \ge 0; equality exactly at a=ba = b.
  • Recovery: from AA and GG, the pair satisfies a+b=2Aa + b = 2A, ab=G2ab = G^2, so (ab)2=4(A2G2)(a-b)^2 = 4(A^2 - G^2) and the numbers are A±(A+G)(AG)A \pm \sqrt{(A+G)(A-G)}.
  • Quadratic link: roots with A.M. α\alpha and G.M. β\beta satisfy x22αx+β2=0x^2 - 2\alpha x + \beta^2 = 0.
  • Optimisation: fixed sum \Rightarrow product maximised at equality; x+1x2x + \frac{1}{x} \ge 2 for x>0x > 0.

JEE Quick Card — A.P., Infinite G.P., Special Series

  • A.P.: an=a+(n1)da_n = a + (n-1)d; Sn=n2[2a+(n1)d]=n2(a+l)S_n = \frac{n}{2}[2a + (n-1)d] = \frac{n}{2}(a + l); symmetric terms ad,a,a+da-d, a, a+d; inserting nn A.M.s uses d=ban+1d = \frac{b-a}{n+1}.
  • Infinite G.P.: S=a1rS_\infty = \frac{a}{1-r} for r<1|r| < 1; given SS and aa, r=1aSr = 1 - \frac{a}{S}.
  • Recurring decimals: 0.d1d2=d1d2990.\overline{d_1 d_2} = \frac{\overline{d_1 d_2}}{99} — an infinite G.P. with ratio 1100\frac{1}{100}.
  • Special series: k=n(n+1)2\sum k = \frac{n(n+1)}{2}; k2=n(n+1)(2n+1)6\sum k^2 = \frac{n(n+1)(2n+1)}{6}; k3=[k]2\sum k^3 = \left[\sum k\right]^2; first nn odd numbers sum to n2n^2.
  • Product series: write the nn-th term as a polynomial in nn, then apply the special sums — k(k+1)=n(n+1)(n+2)3\sum k(k+1) = \frac{n(n+1)(n+2)}{3}.
  • Growth models: compound interest and bacteria multiply (×(1+i)\times (1+i) or ×2\times 2 per period — G.P.); simple interest and fixed instalments add — A.P. Read which one the problem is.
  • Bouncing ball: total distance =h+2hr1r= h + 2 \cdot \frac{hr}{1-r} for rebound fraction rr.

Last-Minute Mistake Checklist

Before the exam, scan this list — each item is a real mark lost by real students:

  1. an=arn1a_n = ar^{n-1}, not arnar^n — the 10th term carries r9r^9.
  2. Two-condition G.P. problems: divide the equations; subtracting them leads nowhere.
  3. The sum formula needs r1r \ne 1; when r=1r = 1 the sum is simply nana.
  4. Inserting nn means makes n+2n + 2 terms — the exponent is n+1n + 1, not nn.
  5. S=a1rS_\infty = \frac{a}{1-r} is valid ONLY for r<1|r| < 1 — quote the condition or lose the mark.
  6. A.M.-G.M. requires POSITIVE numbers; and equality holds only at a=ba = b.
  7. Three-term problems: take ar,a,ar\frac{a}{r}, a, ar (G.P.) or ad,a,a+da-d, a, a+d (A.P.) — the symmetric choice kills one unknown instantly.
  8. "Sum of the series" is a number; "the series" is the expression — examiners distinguish them and so should you.
  9. In growth problems, compound interest multiplies (G.P.) while simple interest adds (A.P.) — misreading this flips the whole model.
  10. rr may be negative — keep both roots of r2=kr^2 = k unless a positivity condition kills one (±4\pm 4 in the 1-to-256 insertion; ±3\pm 3 when r2=9r^2 = 9).