How NEET Tests This Chapter
Semiconductors reliably supply 1-2 NEET questions from a compact pool:
- Classification & bands: gap orderings, majority/minority carriers, dopant identification.
- Junction & bias: depletion-width changes, barrier arithmetic, current scales (mA vs A).
- Rectifiers: output frequencies, circuit identification, filter roles.
- Extras (still in NEET syllabus): Zener regulation, LED/photodiode/solar-cell bias table, logic-gate truth tables and identification.
- Numericals: mass-action law, simple diode circuits with cut-in subtraction.
Everything below is NEET-style previous-year material with fully worked explanations. Years are attached only where attribution is certain; otherwise the tag is the generic [NEET].
Anchors: gaps C/Si/Ge = 5.4/1.1/0.7 eV; cut-ins Ge/Si = 0.2/0.7 V; ripple half/full = f/2f; bias table LED-forward, photodiode-reverse, solar-cell-none.
NEET PYQ Worked Set A: Materials & Carriers
PYQ 1. In a p-type semiconductor, the acceptor level lies: [NEET]
Solution:
- Slightly above the top of the valence band () — a small hop ionises the acceptor, releasing a hole.
PYQ 2. Si doped with phosphorus becomes: [NEET]
Solution:
- P is pentavalent → donor → n-type; electrons majority.
PYQ 3. The forbidden gap of an insulator, semiconductor and conductor compare as: [NEET]
Solution:
- Insulator > 3 eV; semiconductor < 3 eV; conductor ≈ 0 (overlap).
PYQ 4. A semiconductor at 0 K behaves as: [NEET]
Solution:
- An insulator — full valence band, empty conduction band, no carriers.
PYQ 5. For a doped sample, m⁻³ and m⁻³: find and the type. [NEET]
Solution:
- m⁻³.
- : n-type.
NEET PYQ Worked Set B: Junction, Diode & Rectifier
PYQ 6. In an unbiased junction, the motion of holes p → n is due to: [NEET]
Solution:
- The concentration gradient (holes abundant on p, scarce on n) — diffusion, not the field (which opposes it).
PYQ 7. Under reverse bias, the depletion width and barrier height: [NEET]
Solution:
- Both increase — barrier , wider space-charge region.
PYQ 8. Which meter measures a diode's reverse current? [NEET]
Solution:
- Microammeter — reverse saturation is A scale (forward mA needs a milliammeter).
PYQ 9. A full-wave rectifier on 60 Hz mains gives ripple at: [NEET]
Solution:
- 2 × 60 = 120 Hz.
PYQ 10. A Si diode (0.7 V) with 300 ohm across 3.7 V forward: the current is: [NEET]
Solution:
- mA.
PYQ 11. In the half-wave rectifier, during the diode's non-conducting half-cycle the output voltage is: [NEET]
Solution:
- Zero — the diode blocks; the entire (peak) secondary voltage appears across the DIODE in reverse.
NEET PYQ Worked Set C: Extras (Zener, Optoelectronics, Gates)
PYQ 12. Match the device to its bias: LED, photodiode, solar cell. [NEET]
Solution:
- LED: forward (radiative recombination of injected carriers).
- Photodiode: reverse (A photo-signal detectable atop A dark current).
- Solar cell: no bias (built-in field separates photo-carriers; generates power).
PYQ 13. A Zener ( = 5 V, = 1 kohm) on a 12 V supply with a 1 kohm load: find . [NEET]
Solution:
- mA; mA.
- mA.
PYQ 14. The gate whose output is 0 only when all inputs are 1: [NEET]
Solution:
- NAND — ; the (1,1) → 0 signature.
PYQ 15. Inputs A = 0, B = 0 into a NOR gate give: [NEET]
Solution:
- — NOR's lone 1, its signature row.
PYQ 16. An LED begins to emit only above ~1.8 V forward voltage while a Si diode conducts at 0.7 V. Why the higher turn-on? [NEET]
Solution:
- The LED's material has a larger band gap (1.8-3 eV for visible emission).
- The turn-on voltage tracks — more gap, more volts before injection floods the junction.
- Takeaway: turn-on voltage ≈ band gap in volts — red LEDs ~1.8 V, blue ~3 V.