How to Use This Problem Set

This is your full workout for Coordination Compounds, grouped by theme: oxidation number and coordination number, IUPAC nomenclature, isomerism, VBT (hybridisation and magnetic moment), and CFT (splitting, high/low spin, CFSE).

Keep these handy:

  • Spin-only moment: μ=n(n+2)\mu = \sqrt{n(n+2)} BM (1.73, 2.83, 3.87, 4.90, 5.92 for n=1n=1 to 5).
  • VBT: sp3sp^3 tetrahedral, dsp2dsp^2 square planar, sp3d2sp^3d^2 outer octahedral, d2sp3d^2sp^3 inner octahedral.
  • Spectrochemical (weak to strong): I^- < Cl^- < F^- < H2_2O < NH3_3 < en < CN^- < CO.
  • Octahedral CFSE =(0.4nt2g+0.6neg)Δo= (-0.4\,n_{t_{2g}} + 0.6\,n_{e_g})\Delta_o.

Solved Examples - Oxidation & Coordination Number

Example 1. Oxidation number of Fe in K4_4[Fe(CN)6_6]?

Solution: In [Fe(CN)6]4[\text{Fe(CN)}_6]^{4-}, let oxidation state of Fe be xx. Since each CN^- is 1-1, x6=4x=+2x-6=-4\Rightarrow x=+2.

Example 2. Coordination number of Co in [Co(en)3_3]3+^{3+}?

Solution: en is bidentate, so 3×2=63\times 2=6.

Example 3. Oxidation number of Pt in [Pt(NH3_3)2_2Cl2_2]?

Solution: NH3_3 is neutral and 2 Cl^- contribute 2-2. For a neutral complex, x2=0x=+2x-2=0\Rightarrow x=+2.

Solved Examples - Nomenclature

Example 4. IUPAC name of [Co(NH3_3)6_6]Cl3_3?

Solution: hexaamminecobalt(III) chloride.

Example 5. IUPAC name of K3_3[Fe(CN)6_6]?

Solution: potassium hexacyanidoferrate(III).

Example 6. Formula for tetraamminecopper(II) sulphate?

Solution: [Cu(NH3_3)4_4]SO4_4.

Solved Examples - Isomerism

Example 7. What isomerism does [Co(NH3_3)5_5(NO2_2)]2+^{2+} show?

Solution: Linkage isomerism, because NO2_2^- is ambidentate and can coordinate through N (nitro) or O (nitrito).

Example 8. How many geometric isomers does [Co(NH3_3)4_4Cl2_2]+^+ have?

Solution: Two: cis and trans.

Example 9. Total stereoisomers of [Co(en)2_2Cl2_2]+^+?

Solution: 3: trans is one form, and cis exists as an enantiomeric pair.

Solved Examples - VBT

Example 10. Hybridisation and magnetism of [Co(NH3_3)6_6]3+^{3+}?

Solution: Co3+^{3+} is d6d^6. With NH3_3 and the +3 oxidation state, the complex is low spin and uses d2sp3d^2sp^3 hybridisation, octahedral geometry, 0 unpaired electrons, and is diamagnetic.

Example 11. Hybridisation of [NiCl4_4]2^{2-}?

Solution: Ni2+^{2+} is d8d^8. With weak-field Cl^- ligands, it is sp3sp^3, tetrahedral, with 2 unpaired electrons, so it is paramagnetic.

Example 12. Hybridisation of [Ni(CN)4_4]2^{2-}?

Solution: Ni2+^{2+} is d8d^8. With strong-field CN^-, it is dsp2dsp^2, square planar, with 0 unpaired electrons, so it is diamagnetic.

Solved Examples - VBT Magnetic Moments

Example 13. Spin-only moment of [NiCl4_4]2^{2-}?

Solution: It has 2 unpaired electrons, so μ=2(2+2)=8=2.83\mu = \sqrt{2(2+2)} = \sqrt{8} = 2.83 BM.

Example 14. Spin-only moment of [Fe(CN)6_6]3^{3-}?

Solution: Fe3+^{3+} is d5d^5. CN^- is strong-field, so the complex is low spin with 1 unpaired electron. Hence μ=1(1+2)=3=1.73\mu = \sqrt{1(1+2)} = \sqrt{3} = 1.73 BM.

Example 15. Spin-only moment of [Fe(H2_2O)6_6]3+^{3+}?

Solution: Fe3+^{3+} is d5d^5. H2_2O is weak-field, so the complex is high spin with 5 unpaired electrons. Hence μ=5(5+2)=35=5.92\mu = \sqrt{5(5+2)} = \sqrt{35} = 5.92 BM.

Solved Examples - CFT

Example 16. t2g_{2g}/eg_g configuration of low-spin d6d^6?

Solution: t2g6eg0t_{2g}^6 e_g^0, with 0 unpaired electrons.

Example 17. Unpaired electrons in [Mn(H2_2O)6_6]2+^{2+}?

Solution: Mn2+^{2+} is d5d^5. H2_2O is weak-field, so the complex is high spin with 5 unpaired electrons.

Example 18. CFSE of an octahedral d3d^3 ion (in Δo\Delta_o)?

Solution: t2g3t_{2g}^3: 3(0.4Δo)=1.2Δo3(-0.4\Delta_o) = -1.2\Delta_o.

Solved Examples - CFT & Colour

Example 19. Is [Fe(CN)6_6]4^{4-} high or low spin?

Solution: Fe2+^{2+} is d6d^6. CN^- is strong-field, so it is low spin with configuration t2g6t_{2g}^6 and 0 unpaired electrons.

Example 20. Why is [Zn(H2_2O)6_6]2+^{2+} colourless?

Solution: Zn2+^{2+} is d10d^{10}, so no dddd transition is possible.

Example 21. Which absorbs shorter-wavelength light: aqua or cyanido complex of the same metal?

Solution: The cyanido complex, because stronger-field ligands produce a larger Δo\Delta_o, so they absorb higher-energy, shorter-wavelength light.

Solved Examples - Stability & Applications

Example 22. Why is [Ni(en)3_3]2+^{2+} more stable than [Ni(NH3_3)6_6]2+^{2+}?

Solution: Because of the chelate effect, which gives a favourable entropy increase.

Example 23. Oxidation state of Ni in Ni(CO)4_4?

Solution: 0, because CO is neutral and the molecule is neutral.

Example 24. Central metal in chlorophyll?

Solution: Magnesium (Mg).

Solved Examples - Mixed

Example 25. Coordination number of Pt in [PtCl6_6]2^{2-}?

Solution: 6, because there are six unidentate Cl^- ligands.

Example 26. Number of ions from [Co(NH3_3)6_6]Cl3_3 in solution?

Solution: 4 ions: one complex cation and three Cl^- ions.

Example 27. Hybridisation of octahedral [CoF6_6]3^{3-}?

Solution: Co3+^{3+} is d6d^6. F^- is weak-field, so the complex is outer orbital, sp3d2sp^3d^2, with 4 unpaired electrons.

Example 28. Geometry of [Ni(CO)4_4]?

Solution: Tetrahedral, with sp3sp^3 hybridisation; Ni is in oxidation state 0 and the complex is diamagnetic.

Solved Examples - Mixed (continued)

Example 29. IUPAC name of [Ni(CO)4_4]?

Solution: tetracarbonylnickel(0).

Example 30. Which is optically active: cis or trans [Co(en)2_2Cl2_2]+^+?

Solution: cis, because the trans form has a plane of symmetry.

Example 31. Spin-only moment of [Ti(H2_2O)6_6]3+^{3+} (Ti3+^{3+}, d1d^1)?

Solution: It has 1 unpaired electron, so μ=1(1+2)=3=1.73\mu = \sqrt{1(1+2)} = \sqrt{3} = 1.73 BM.

Example 32. Denticity of EDTA4^{4-}?

Solution: Hexadentate, because it can bind through 6 donor atoms.